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Ohms Law and Resistance


Published on Jan 07, 2019

Abstract

What drives current? We can think of various devices—such as batteries, generators, wall outlets, and so on—which are necessary to maintain a current. All such devices create a potential difference and are loosely referred to as voltage sources. When a voltage source is connected to a conductor, it applies a potential difference V that creates an electric field. The electric field in turn exerts force on charges, causing current.

Objective

Our objective is to determine the resistance per centimeter of a given wire by plotting a graph of potential difference versus electric current

Theory

According to the Ohm's law, "The electric current flowing through a conductor is directly proportional to the potential difference across its ends provided the physical conditions (temperature, dimensions, pressure) of the conductor remains the same."

If I is the current flowing through a conductor and V is the potential difference across its ends, then according to Ohm's Law,

Ohms Law

where, R is the constant of proportionality. It is known as resistance of the conductor, or

Ohms Law

R depends upon the material, temperature and dimensions of the conductor.

In S.I. units, the potential difference 'V' is measured in volt and the current 'I' in ampere, the resistance 'R' is measured in ohm.

Ohms Law

To establish the current-voltage relationship, it is to be shown that the ratio V / I remains constant for a given resistance and therefore a graph between the potential difference(V) and the current (I) must be a straight line.

The value of unknown resistance can be calculated using the equation ,

R = V / I

Here R is a constant.

To find the length of the resistance wire, l. Then

R / I ............. (2)

This gives the resistance per unit cm.

Materials Required:

• Lead Accumulator or battery eliminator

• Ammeter

• Voltmeter

• A resistance wire

• Rheostat

• One way Key

• Metre Scale

• Connecting wires

Procedure:

1. Draw the circuit diagram.

2. Arrange the required materials on the table.

3. Make the connections according to the circuit diagrams.

4. Determine the least count of the voltmeter and ammeter, and also note the zero error, if any.

5. Insert the key K, then slide the rheostat contact and see that the ammeter and voltmeter are working properly.

6. Adjust the sliding contact of the rheostat such that a small current passes through the resistance coil or the resistance wire.

7. Note down the value of the potential difference (V) from the voltmeter and current (I) from the ammeter.

8. Shift the rheostat contact slightly so that both the ammeter and voltmeter show full divisions readings.

9. Record the readings of the voltmeter and ammeter.

10. In each case V/I is calculated, which gives the resistance R of the resistor and it is found as a constant.

11. Take at least six sets of independent observations.

12. Cut the resistance wire at the points where it leaves the terminals, stretch it and find its length by the meter scale.

13. A graph is drawn with I along the X-axis and V along the Y-axis. The graph obtained is a straight line. This also verifies Ohm’s law.

14. Note a particular point of current on X axis and extend a line joining the straight line and the point on Y axis. Mark these points.

15. Note the values of OB and AB then calculate the value of R as AB/OB.

16. Calculate the resistance per cm of the resistance wire can be found out by using the equation 2.

Observations:

Length of the resistance wire l = ......cm

Least count of ammeter = .......A.

Least count of voltmeter = .......V.

Zero correction for ammeter, (-e1) = .......A.

Zero correction for voltmeter, (-e2) = ......V.

Ohms Law

Mean value of resistance, R = ....................ohms.

Length of the resistance wire, l=…………cm

Resistance per cm , R / l =…………..Ωcm-1

Result:

Resistance per cm of the wire is ........................ Ω cm-1.

References

Books

• Manual of Secondary Science Kit for Classes IX and X - Published by NCERT

Websites

• https://www.youtube.com/embed/4-GxinG7AVw?rel=0&vq=hd1080

• https://www.youtube.com/embed/Ls5_PcXZRc8?rel=0&vq=hd1080





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